If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-20x+15=x+5
We move all terms to the left:
x^2-20x+15-(x+5)=0
We get rid of parentheses
x^2-20x-x-5+15=0
We add all the numbers together, and all the variables
x^2-21x+10=0
a = 1; b = -21; c = +10;
Δ = b2-4ac
Δ = -212-4·1·10
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{401}}{2*1}=\frac{21-\sqrt{401}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{401}}{2*1}=\frac{21+\sqrt{401}}{2} $
| 7=-7r | | 15+3x=2(-x+9)-23 | | 4m+7=35m= | | 1.5-2x=6.5 | | 11+1/2x=7 | | 8t-3=5t+15 | | 4f-7=37 | | 5=3x−10 | | -6(7-8x)=4+2x | | 4(−4x+3)−3x+4=-174 | | 8=14n | | -12+4p=-7(2p-6) | | -3(v+1)=7v-3+2(2v+6) | | 6p+3=4p+7 | | 5/9=y+4 | | -14x=-20 | | r+4=-8-3r+2r | | -8=-3a | | 51=4x-9 | | 2(x+10)=-4(x+1) | | -8=-14y | | 3(2x+1)-2x=3(x+3) | | 4r+1=2r+11 | | 4-(3x+4)=3-x | | -4(4u-2)+5u=4(u+5) | | 4(3x-2)-2x=3(2x+4) | | 4r+1=2r=11 | | 4x^-30=34 | | 6w+5=42 | | 3(x+7)=2(4x+18 | | 6-8m=-4+2m | | 21=p-8p |